#include <stdio.h>
#include <stdlib.h>
#include <string.h>

short a[10000];
short sets[10000];
short p[10000];

int main()
{
  long i,n;
//  freopen("input.txt","rt",stdin);
//  freopen("output.txt","wt",stdout);

  while (scanf("%ld",&n)==1)
  {
  if (n==1) { printf("1\n"); continue; }
    long k,j,sum;
    sum=0;

    memset(a,0,sizeof(a));
    memset(sets,0,sizeof(sets));

    for (i=0; i<n; i++)
    {
      scanf("%ld",&k);
      for(j=2; j<=k; j++) a[j]--;
      sets[k]++;
      sum+=k;
    }
    for(j=2; j<=sum; j++) a[j]++;
    for(i=1; i<=sum; i++)
      for(j=2; j<=sets[i]; j++) a[j]--;

    memset(p,0,sizeof(p));
    unsigned long result=1;
    for(i=2; i<=sum; i++)
    if(!p[i])
    {
      j=i+i;
      while (j<=sum)
    { p[j]=1;
      k=j;
      while(k%i==0) {
        k/=i;
        a[i]+=a[j];
      }
      j+=i;
    }

      for(j=a[i]; j>=1; j--) result*=i;
    }
    printf("%lu\n",result);
  }

  exit(0);
  return 0;
}

>

> >

You've made a terrible mistake. What does it mean "sum+=k"? IS NOT A
PASCAL STYLE! Use "sum=sum+k"!

Crazy Lemming you are not very informed with C and C++!
It can be done in the way you say and in the way he made it!
In c++ and in C(as i suppose) sum+=k adds k to sum!
In pascal can be different but in C or C++ it isn't!

Edited by author 06.06.2008 13:04

Edited by author 06.06.2008 13:04