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back to boardDo not seek any kind of logic in this problem just paste this! (+) Posted by nullman 18 Jan 2003 23:09 I think that there must be some 'X' one after another, because it is said 'ai*X^(n-1)' like this for n=2: 0 X X * * 1 --> I'm only not quite sure for this '1' X * --> and if there is no '1' this row also turns off + 2 + I have tried to write something but it sucked, so I got a Pascal code and turned it to C++! AC 0.02 sec /////////////////////////////////////////////// // 1059 #include <stdio.h> int i,n; int main() { scanf("%d",&n); puts("0"); for (i=1;i<=n;i++) printf("X\n*\n%d\n+\n",i); //getch(); return 0; } ///////////////////////////////////////////////// |
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