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вернуться в форумShortest AC program: if(m<=2)f=n;else for(f=m;n-->m;f+=(f-m)/(m-2)*2+3); Can anybody do better? Re: Shortest AC program: if(m<=2)f=n;else for(f=m;n-->m;f+=(f-m)/(m-2)*2+3); Can anybody do better? Послано PSV 5 ноя 2006 21:39 Man you have compilation error :) Re: Shortest AC program: if(m<=2)f=n;else for(f=m;n-->m;f+=(f-m)/(m-2)*2+3); Can anybody do better? Can anybody tell how to deduce this solution? No subject It is a wrong solution |
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