#include <iostream.h>
#include <stdio.h>

float A,B;
int K;

float S (long a, long b)
{
 return a*A+b*B-a*a-b*b;
}

float Maxsb (long a, long& b)
{
 b=B/2;
 if (b<0) b=0;
 if (b+a>K)
  b=K-a;
 return S (a,b);
}

int main ()
{
 cin >> A >> B >> K;
 float max=0,maxsb;
 int ma=0,mb=0;
 long a,b;
 for (a=0;a<=K;a++)
 {
  maxsb=Maxsb (a,b);
  if (maxsb>max)
  {
   max=maxsb;
   ma=a;
   mb=b;
  }
 }
 printf ("%.2f\n",max);
 printf ("%d %d\n",ma,mb);
 return 0;
}

I think that operator b=B/2 is incorrect. b must be closest integer for B/2.
For example, if A=2, B=1.8 and K=100 then rigth answer is ma=1 and mb=1.

> I think that operator b=B/2 is incorrect. b must be closest integer
for B/2.
> For example, if A=2, B=1.8 and K=100 then rigth answer is ma=1 and
mb=1.

the maximum of a 2 degree function is at point -b/2a, in our case b/2...

brute force works fine... :D