|
|
back to boardCan anybody help me with P1204?If so,please send message to "flyingbluecat@hotmail.com". Re: Can anybody help me with P1204?If so,please send message to "flyingbluecat@hotmail.com". Posted by Yuan 19 Mar 2002 15:25 because x*x=x (mod pq) so x*x=kpq+x x(x-1)=kpq p, q are distinct prime, so case 1 p|x, q|x-1 case 2 p|x-1, q|x for the first case, we have pa=x, qb=x-1, so pa-qb=1 ... |
|
|