Where do the intervals start from? And why doesn't it matter the
legth of the tram travels? I mean, it must matter for the interval of
the trams....... Explain PLZ

any time the robber come to the i-th stop, he have to wait for ti (time
interval) minutes ,a tram will come and the interval starts.

most of problems in this contest are very ambigious, i had to guest
many times to know what they want.

please explain me about 1190

First, 10x about the explanation. I'll try to solve it having that in
mind.
About 1190-> I had problems with understanding it, too. Maybe you
should read the comments on board 1190. Some people helped me there.
You should have these in mind :
0) Percents should be non-increasing, not strictly decreasing
1) Names contain no intervals
2) Try both the possiblities-> the maximum one and the minimum one.
If the maximum is less than 10000, then NO. If the minimum is more
than 10000 than NO again. If the percents are not non-increasing->
NO. Otherwise-> YES.

You should get AC with that.

and what about the policeman? does he have to wait ti as well?
Because, if the counting for him starts with the arrival of the
robber at the tram stop, then it DOES matter the length of the
route... So, does the policeman have to wait ti minutes as well?
Another question-> If the distance (the lag-> L) is 2, and t1 is 2,
does the policeman catch the robber

15 4
7 3 13 6

1st stop
robber is here at time 0
and he go out when time 0+7
police is here at time 15
the next tram will come at time 21 (trams come at 7,14,21)

the length of route doesn't matter the time lag at all because their speed
are always equal. so i'll assume that it's 0.
2nd stop
robber arrive at 7
robber go 7+3=10
police arrive 21
police go 22 (10,13,16,19,22)

3rd stop
robber go 10+13 = 23
police come 22 and arrest the robber here before he can go

#include <stdio.h>

int main() {
int cop,n,ti,rob,i,st,ost,tmp;
    scanf("%d %d",&cop,&n);
    for (i=1;i<=n;i++) {
        scanf("%d",&ti);
        st=rob;
        rob+=ti;
       if (rob>=cop) {
           printf("YES\n");
           return 0;
        }
        st=cop-st;
        ost=st%ti;
        if (ost==0) ost=ti;
        cop+=(ti-ost);
    }
    printf("NO\n");
    return 0;
}



I tried with if (rob>cop) but I got WA. I tried to compare the
leaving times(i mean, compare the time when the cop catches the tram
and the time the robber catches the tram, and if they are the same or
the cop can catch an earlier tram, then YES... but WA too. What I do
is just implementing stepwisely what you told me-> in 'cop' i keep
the time of the cop, and in 'rob' the time of the robber... But WA.
Help plz?

> #include <stdio.h>
>
> int main() {
> int cop,n,ti,rob,i,st,ost,tmp;
>     scanf("%d %d",&cop,&n);
>     for (i=1;i<=n;i++) {
>         scanf("%d",&ti);
>         st=rob;
>         rob+=ti;
>        if (rob>=cop) {
>            printf("YES\n");
>            return 0;
>         }
>         st=cop-st;
>         ost=st%ti;
>         if (ost==0) ost=ti;
>         cop+=(ti-ost);
>     }
>     printf("NO\n");
>     return 0;
> }

1.) initialize the variable rob to be 0!
2.) problem statement says "the policeman will have luck to overtake the
robber. For instance, if L *****<***** K1, then it may happen that
the policeman will reach the first stop, when the robber is still waiting
for the tram there." this implies that , if police reach the stop when the
robber is leaving , he just have to wait from the next tram.
so use condition "rob>cop" and comment "if (ost==0) ost=ti;" and you'll
get AC!

>

Thank you very much!

好像不是这样的吧？
我WA#3

I don't think the statement is clearly, it may mislead someone like me...