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вернуться в форумMy solution Послано Pearl 4 окт 2018 04:27 First, let give the bits some names, I put them inside the parentheses: Petal 1 (p1) = II (c2) + III (c3) + IV (c4) Petal 2 (p2) = I (c1) + III (c3) + IV (c4) Petal 3 (p3) = I (c1) + II (c2) + IV (c4) As p1, p2 and p3 are created from c1, c2, c3, c4, we check each change in c1, c2, c3, c4: When c1 change: p2 and p3 won't match the value calculated using the formular above (i.e: c1 + c3 + c4 != p2 and c1 + c2 + c4 != p3) When c2 change: p1 and p3 will go wrong When c3 change: p1 and p2 will go wrong As c4 contribute to the value of all three petals, if it is changed then p1, p2 and p3 will all go wrong. In short: Calculate ep1, ep2 and ep3 from the first 4 bits (the e in ep stand for expected), then compare them with the given p1, p2 and p3: All three pairs do not match: c4 is changed p1 and p2 do not match: c3 is changed p1 and p3 do not match: c2 is changed p2 and p3 do not match: c1 is changed Only p1 not match: p1 is changed Only p2 not match: p2 is changed Only p3 not match: p3 is changed |
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