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вернуться в форумSolution using SQRT_DECOMPOSITION Послано iOli 19 апр 2018 22:18 #include <bits/stdc++.h> using namespace std; int query(int l, int r, vector<int> bucket, vector<int> v) { int n = v.size(); int bkt_sz = sqrt(n); int bkts = bucket.size();
int lb = l/bkt_sz; int rb = r/bkt_sz; int lbp = l%bkt_sz; int rbp = r%bkt_sz;
int retval = -1;
if (lb == rb) { for (int i=lb*bkt_sz+lbp; i <= lb*bkt_sz+rbp; i++) retval = max(retval, v[i]); return retval; }
for (int i=lb+1; i < rb; i++) retval = max(retval, bucket[i]);
for (int i=lb*bkt_sz+lbp; i<n; i++) { if (i >= (lb+1)*bkt_sz) break; retval = max(retval, v[i]); }
for (int i=rb*bkt_sz; i <= rb*bkt_sz+rbp; i++) { retval = max(retval, v[i]); }
return retval; } int main() {
int k; cin >> k;
vector<int> v;
while (true) { int a; cin >> a; if (a == -1) break; v.push_back(a); }
int n = v.size(); int bkt_sz = sqrt(n);
vector<int> bucket;
int count = bkt_sz; int max_value = -1; for (int i=0; i<n; i++) { if (count == 0) { count = bkt_sz; bucket.push_back(max_value); max_value = -1; } count -= 1; max_value = max(max_value, v[i]); }
bucket.push_back(max_value);
for (int i=0; i+k-1 < n; i++) { cout << query(i, i+k-1, bucket, v) << endl; }
} Edited by author 19.04.2018 22:19 |
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