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back to boardWhy so? f(x) = k * (x^2 -2(a1)x + (a1)^2 + x^2 -2(a2)x + (a2)^2 + ... + x^2 -2(an)x + (an)^2) / n = k (x^2 - (2/n)(a1 + a2 + ... + an)x + ((a1)^2 + (a2)^2 + ... + (an)^2)/n so we have f'(x) = k(2x - (2/n)(a1 + a2 + ... + an)) question: what is k? (explaining from previus post) Edited by author 05.05.2016 14:53 Edited by author 05.05.2016 14:54 |
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