x^2 + y^2 = A * p + k;
you use this simple algorithm:
A = [0....p]
and simple Check:
first time : y = 0 and x = sqrt(A*p + k)
if(x*x == A*p + k) you should Print this answer: x and y
else
second time: x = (int) sqrt(A*p + k) and y = sqrt(A*p + k - (int)x*x)
if(x*x + y*y == A*p + k) you should Print this answer : x and y
else continue and increasing only ONE count of A

Sorry my English...

Edited by author 04.01.2014 13:44

Edited by author 26.05.2014 22:39

x  and  y  are INTEGER....