#include <iostream>
using namespace std;
int main()
{
int k,n,l=1;
int r=0;
int* a = new int[1];
cin >> k >> n;
cin >> a[0];
for(int i=1;cin >> a[i];i++) l+=1;
for(int i=0;i<n;i++){
    if(i<l) r+=a[i];
    r-=k;
    if(r<0) r=0;
}
cout << r << endl;
system("pause");
return 0;
}

Что не так?

Edited by author 06.11.2013 23:12

int* a = new int[1];

LOLWUT?

This is a dynamic array. The number in [] has no importance. An array is okay

Edited by author 06.11.2013 23:14

RTFM:
1. http://en.wikipedia.org/wiki/New_(C++)#Syntax
2. http://www.cplusplus.com/reference/new/operator%20new[]/

BTW, did you came from Java? In C++, there is no garbage collectors, so you must release memory manually to avoid memleaks, by calling delete operator ( in this case - delete[] ).


Edited by author 07.11.2013 00:40

All right. Thanks for the information. But I find it hard to understand how I should use it in the program. Please correct my code ..

In this case, just don't use pointers. You can declare an array using following syntax:
Typename variableName[ arraySize ];

Exapmle:
int array[ 100 ];
In this example, an array of 100 int elements will be created.

I suppose, that most of problems from archive can be solved without using dynamic memory allocation.


Edited by author 07.11.2013 12:30

Thanks for the help

попробуйте
5 5
0 0 0 0 0