what is test case 7?
I think my doing well.
#include<stdio.h>
int main()
{
    int n,val[1001],pos1=2,pos2=1,sum[1001];
    scanf("%d",&n);
    for(int i=1;i<=n;i++)
        scanf("%d",&val[i]);
    for(int i=2;i<=n-1;i++)
    {
        sum[i]=val[i-1]+val[i]+val[i+1];
    }
    for(int i=2;i<=n-1;i++)
    {
        if(sum[i]>=sum[i+1])
        {
            sum[i+1]=sum[i];
            pos2++;
        }
        else if(sum[i]<sum[i+1])
        {
            pos1+=pos2;
            pos2=1;
        }
    }
    printf("%d %d",sum[n-1],pos1);
}