#include <iostream>
int main()
{
int n,k,a;
std::cin>>n>>k;
if ((2*n)%k==0)
a=(2*n-(2*n)%k)/k;
else  a=(2*n-(2*n)%k)/k+1;

std::cout<<a;
return 0;
}

wrong answer
po4emu ne pravilno, ved algoritm verni?

Edited by author 25.10.2012 22:40

Edited by author 25.10.2012 22:40

if ((n%k)*2<=k) {answer=3;}