Hi,
better post your code, it's faster to find a mistake.

i got past that  now i am stuck at test 9

int main()
{
int a1[4000],b1[4000],c1[4000],g1[4000],g2[4000],a,b,c,i,j,k=0,m,n=0;
scanf("%d",&a);
for(i=0;i<a;i++)
{
scanf("%lu",&a1[i]);
}

scanf("%d",&b);

for(i=0;i<b;i++)
{
scanf("%lu",&b1[i]);
}


scanf("%d",&c);
for(i=0;i<c;i++)
{
scanf("%lu",&c1[i]);
}

for(i=0;i<a;i++)
{
for(j=0;j<b;j++)
{
if(a1[i]==b1[j])
{
g1[k]=a1[i];
k++;
}
}
for(m=0;m<c;m++)
{
if(a1[i]==c1[m])
{
g2[n]=c1[m];
n++;
}
}
}
if(n>=k)
{
printf("%d",k);
}
else
{
printf("%d",n);
}
return 0;
}

int main()
{
int a1[4000],b1[4000],c1[4000],g1[4000],g2[4000],a,b,c,i,j,k=0,m,n=0;
scanf("%d",&a);
for(i=0;i<a;i++)
{
scanf("%lu",&a1[i]);
}

scanf("%d",&b);

for(i=0;i<b;i++)
{
scanf("%lu",&b1[i]);
}


scanf("%d",&c);
for(i=0;i<c;i++)
{
scanf("%lu",&c1[i]);
}

for(i=0;i<a;i++)
{
for(j=0;j<b;j++)
{
if(a1[i]==b1[j])
{
g1[k]=a1[i];
k++;
}
}
for(m=0;m<c;m++)
{
if(a1[i]==c1[m])
{
g2[n]=c1[m];
n++;
}
}
}
if(n>=k)
{
printf("%d",k);
}
else
{
printf("%d",n);
}
return 0;
}

You solution doesn't seem to be right. As far as I see, you have in g1 the common values from A and B, and in g2 the common values from A and C. Then, you output the size of the smaller array (g1 or g2).
This is not correct, as you don't intersect B with C. Here's a counter-example:
5
2 3 4 5 6
5
3 4 5 6 7
5
1 2 3 4 5
Your output is 4 but correct is 3.

Edited by author 21.01.2012 04:48

Edited by author 21.01.2012 04:49

thank you morbidel

Edited by author 19.04.2012 05:39