Discussion @ 1893. A380 @ Timus Online Judge

Nguyen Khac Tung Row 1 & 2 [5] // Problem 1893. A380 30 Oct 2011 21:27

As i read the problem, the configuration of two first rows are :

Window | A | Aisle | B | C | Aisle | D | Window

I check with my program and for 1A 'window' is AC while 'aisle' gives WA6

Edited by author 30.10.2011 20:54

Edited by author 30.10.2011 20:54

larev01 Re: Row 1 & 2 [4] // Problem 1893. A380 3 Apr 2012 14:27

Wrong. The configuration is:
Window |A||B| Aisle |C||D| Window

Victor Re: Row 1 & 2 [3] // Problem 1893. A380 18 Apr 2012 03:53

Why would the configuration be that way? "The aisles in this section are between the first and second seats and between the third and fourth seats of each row." That means that the configuration
Window | A | Aisle | B | C | Aisle | D | Window
is correct

SquidBoy Re: Row 1 & 2 [2] // Problem 1893. A380 27 Apr 2012 05:10

That is the configuration, however the problem requires:
"If the seat is next to the window, output “window”. Otherwise, if the seat is next to the aisle, output “aisle”. If neither is true, output “neither”. "

This implies if it is both an aisle and a window, the correct answer is window.
(if window print window, else if aisle print aisle, else print neither)

Vohidjon Re: Row 1 & 2 [1] // Problem 1893. A380 6 Feb 2015 01:29

Hey, man. Thanks a lot for your help

abdur rahman shajib Re: Row 1 & 2 // Problem 1893. A380 12 Oct 2018 01:46

thanks bro for your help :-)

Discussion of Problem 1893. A380