WA#17 Posted by sklyack 12 Apr 2010 02:28 Have anybogy gotten? Re: WA#17 Posted by sklyack 12 Apr 2010 03:14 I shocked... when I input/output like this ... scanf("%I64d%I64d%I64d%I64d%I64d%I64d%I64d%I64d", &x01, &y01, &x1, &y1, &x02, &y02, &x2, &y2); ... printf("%I64d", intersect); ... I got WA#17, and when I instead of that wrote this ... cin>>x01>>y01>>x1>>y1>>x02>>y02>>x2>>y2; ... cout<<intersect; ... I got AC! Why? Doesn't the "scanf" correctly read __int64 numbers? P.S. Sorry for my english. Re: WA#17 Posted by Ego 12 Apr 2010 23:32 i used scanf. it works scanf("%I64d%I64d\n%I64d%I64d\n%I64d%I64d\n%I64d%I64d", &x11,&y11, &x12,&y12, &x21,&y21, &x22,&y22); Re: WA#17 Posted by sklyack 12 Apr 2010 23:45 I tried scanf with "\n" -- the same verdict: WA#17 Edited by author 12.04.2010 23:46 Re: WA#17 Posted by Ego 13 Apr 2010 00:47 if all of x01, y01, x1, y1, x02, y02, x2, y2 are 64bit integers (long long or __int64) then i don't know. strange.. Re: WA#17 May be your "intersection" variable either float or double but you print it like 64-bit integer. Try this: printf("%lld", intersect); Re: WA#17 Posted by sklyack 14 Apr 2010 01:05 May be your "intersection" variable either float or double but you print it like 64-bit integer. Try this: printf("%lld", intersect); It gets WA#1. All of variables x01, y01, x1, y1, x02, y02, x2, y2, intersect, have type "long long", so output by printf("%I64d", intersect); must be correct, but it isn't so. Edited by author 14.04.2010 01:06 Edited by author 14.04.2010 01:07Re: WA#17 Posted by sklyack 14 Apr 2010 01:17 If you want, I can send my code on your e-mail, if you got AC, and you will be able to check this phenomenon. Re: WA#17 Posted by Ego 14 Apr 2010 08:12 that would be interesting to look at it. accdead@gmail.com Re: WA#17 Posted by sklyack 14 Apr 2010 22:49 sent. Re: WA#17 I also got WA#17 I don't know what to do Give me some tests please or tell what in my code is wrong #include <iostream> using namespace std; struct Coord { __int64 x; __int64 y; }; bool Sign(__int64 x, __int64 y) { if(x > y) return 1; return 0; } void Sort(Coord* arr) { for(int i = 0; i < 4; i++) { for(int j = i; j < 4; j++) { if((arr[j].x < arr[i].x) || (arr[j].x == arr[i].x && arr[j].y > arr[i].y)) { Coord tmp = arr[j]; arr[j] = arr[i]; arr[i] = tmp; } } } } int main() { Coord crd[4]; for(int i = 0; i < 4; i++) { cin >> crd[i].x >> crd[i].y; } bool sign1 = Sign(crd[0].x, crd[1].x) ^ Sign(crd[0].y, crd[1].y); bool sign2 = Sign(crd[2].x, crd[3].x) ^ Sign(crd[2].y, crd[3].y); __int64 a = -1, b = -1; Coord arr[4]; for(int i = 0; i < 4; i++) { arr[i].x = crd[i].x; if(i < 2) arr[i].y = 0; else arr[i].y = 1; if(i % 2 == 1) { if(arr[i].x < arr[i-1].x) { __int64 tmp = arr[i].x; arr[i].x = arr[i-1].x; arr[i-1].x = tmp; } } } Sort(arr); if(arr[2].y == arr[0].y || arr[2].y == arr[1].y || arr[2].x == arr[0].x || arr[3].x == arr[1].x) a = arr[2].x - arr[1].x; for(int i = 0; i < 4; i++) { arr[i].x = crd[i].y; if(i < 2) arr[i].y = 0; else arr[i].y = 1; if(i % 2 == 1) { if(arr[i].x < arr[i-1].x) { __int64 tmp = arr[i].x; arr[i].x = arr[i-1].x; arr[i-1].x = tmp; } } } Sort(arr); if(arr[2].y == arr[0].y || arr[2].y == arr[1].y || arr[2].x == arr[0].x || arr[3].x == arr[1].x) b = arr[2].x - arr[1].x; if(sign1 == sign2) { cout << a + b << endl; } else { if(a == -1 || b == -1) cout << 0 << endl; if(a > b) cout << a << endl; else cout << b << endl; } return 0; } Re: WA#17 Posted by ASK 17 Nov 2010 21:13 It is the first test where rectangle projections do not intersect. |