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вернуться в форум..I am O(n^2) too and got AC.. I use a very simple algorithm..my code is very short.. *just (for i:=1 to n do)check if the number appears in the A set of numbers after i. *set down the father of each number. *Just output. (i'm sorry that my English is really bad..) var con,temp,i,j:longint; fin:array[1..7500]of boolean; b,a,fa:array[1..7500]of integer; begin {$IFNDEF ONLINE_JUDGE} assign(input,'input.in');reset(input); assign(output,'output.out');rewritE(output); {$ENDIF} reaD(temp); con:=0; while temp<>0 do begin inc(con); a[con]:=temp; inc(b[temp]); read(temp); end; for i := 1 to con do for j := 1 to con+1 do if (not fin[j])and(b[j]=0) then begin fin[j]:=true; fa[j]:=a[i]; deC(b[a[i]]); break; end; for i := 1 to con+1 do begin write(i,':'); for j := 1 to con+1 do if (fa[j]=i)or(fa[i]=j) then write(' ',j); writeln; end; end. Edited by author 13.10.2009 15:09 |
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