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back to board#include <iostream>
using namespace std;
int main()
{
unsigned long long n,m;
cin>>n>>m;
if(m>=n) cout<<2*(n-1)<<endl;
if(n>m) cout <<2*(m-1)+1<<endl;
return 0;
} Orz...My solution is so complex... You can even simpler))
#include <iostream>
using namespace std;
int main()
{
unsigned long long iN, iM;
cin >> iN >> iM;
cout << min(2 * (iN - 1), 2 * (iM - 1) + 1);
return 0;
} You don't really need unsigned long long.
Got AC with unsigned int. |
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