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back to boardMy method Posted by wu hao 28 Jan 2009 03:58 F[i] = Max[F[i-j]*j} (0<i<=20)
1 (i=0)
F[i-3]*3 (i>20)
In this way,you can solve the problem in O(n^2).
Edited by author 28.01.2009 03:58 Re: My method Posted by wayne 29 Mar 2009 19:23 what is 'j' |
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