OK, I had a mistake in zeroing the matrix at the beginning setup.
Now I have AC.

Edited by author 23.02.2009 21:24

test:
3
4 5

Tested for input (on my computer):
3
4 5
this program gave me result:

3 3 4 4 8 8 9 9
3 2 2 4 8 7 7 9
5 2 6 6 10 10 7 11
5 5 6 1 1 10 11 11
13 13 14 0 1 18 19 19
13 12 14 14 18 18 17 19
15 12 12 16 20 17 17 21
15 15 16 16 20 20 21 21

I don't see anything wrong here. Maybe I haven't fully and correctly understood the problem?

Edited by author 11.04.2008 21:42

your num 0 isn't on the correct place

So you mean that I have switched rows and columns?

Well, now I have changed the scanf line from
(...) &a,&b) to
(...) &b,&a)
and now I have the following result for this test:

3 3 4 4 8 8 9 9
3 2 2 4 8 7 7 9
5 2 6 6 10 10 7 11
5 5 6 1 0 10 11 11
13 13 14 1 1 18 19 19
13 12 14 14 18 18 17 19
15 12 12 16 20 17 17 21
15 15 16 16 20 20 21 21

But I still have WA #3 :(
Also, look at the other posts at the forum about this problem and you'll read that people who have exchanged rows with columns have WA #4. I have WA earlier so there must be
something else wrong with my program... :(

So, could somebody give the correct solution for test:

3
4 5

? Maybe I haven't correctly understood this problem?

3 3 4 4 8 8 9 9
3 2 2 4 8 7 7 9
5 2 6 6 10 10 7 11
5 5 6 1 0 10 11 11
13 13 14 1 1 18 19 19
13 12 14 14 18 18 17 19
15 12 12 16 20 17 17 21
15 15 16 16 20 20 21 21

x is row, y is column, I was caught by that (but AFAIK it wasn't WA3)