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Discussion of Problem 1002. Phone Numbers

Two similar codes - diffirent results
Posted by maksay 1 Dec 2007 00:00
Var s:string;
    t,r:array[1..50000] of string;
    m:array[0..150] of longint;
    n,i,j:Longint;
    ex:boolean;
Procedure dfs(v:longint);
Var i,l:Longint;
begin
 if v=length(s) then begin ex:=true;Exit; end;
 i:=1;While (i<=n) {and (not ex)} do
 begin
  l:=length(t[i]);
  if Copy(s,v+1,l)=t[i] then
   begin
    m[v+l]:=i;
    dfs(v+l);
   end;
  Inc(i);
 end;
end;
Procedure papa(v,p:longint);
begin
 if v=0 then Exit;
 papa(v-length(t[m[v]]),v);
 Write(r[m[v]]);
 if p<>0 then Write(' ') else Writeln;
end;
begin
 Readln(s);
 While (s<>'-1') and (not eof) do
  begin
   Readln(n);
   For i:=1 to n do
    begin
     Readln(r[i]);
     t[i]:='';
     For j:=1 to length(r[i]) do
      if (r[i,j]='i') or (r[i,j]='j') then t[i]:=t[i]+'1' else
      if (r[i,j]='a') or (r[i,j]='b') or (r[i,j]='c')  then t[i]:=t[i]+'2' else
      if (r[i,j]='d') or (r[i,j]='e') or (r[i,j]='f')  then t[i]:=t[i]+'3' else
      if (r[i,j]='g') or (r[i,j]='h')  then t[i]:=t[i]+'4' else
      if (r[i,j]='k') or (r[i,j]='l')  then t[i]:=t[i]+'5' else
      if (r[i,j]='m') or (r[i,j]='n')  then t[i]:=t[i]+'6' else
      if (r[i,j]='p') or (r[i,j]='r') or (r[i,j]='s')  then t[i]:=t[i]+'7' else
      if (r[i,j]='t') or (r[i,j]='u') or (r[i,j]='v')  then t[i]:=t[i]+'8' else
      if (r[i,j]='w') or (r[i,j]='x') or (r[i,j]='y')  then t[i]:=t[i]+'9' else
      t[i]:=t[i]+'0';
    end;
   For i:=1 to length(s) do m[i]:=-1;ex:=false;m[0]:=0;dfs(0);
   if n=0 then Writeln('No solution.') else
   if length(s)=0 then Writeln else
   if ex then papa(length(s),0) else
   Writeln('No solution.');Readln(s);
  end;
end.


This code gets WA3, but if i remove comments {and (not ex)} then i've got TL5 - its easy yo understand...but wy small change makes WA?!!