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Обсуждение задачи 1372. Звезда смерти

1372- Ambiguous solution?
Послано svr 28 июн 2007 10:01
It seems that this problem very simple.
Let F=[v1,F1]+...+[vN,FN]- sum of  moments of forces,
where vi=(cos(fi)cos(hi),cos(fi)sin(fi),sin(fi))- vector
of point and Fi=(cos(qi)cos(zi),cos(qi)sin(zi),sin(qi))-
vector of force Fi.
Let V,G- point and force to be found.
Then we have [V,G]=-F,|G|->min;
We must have V- is normal to F=>V any point on meridian
and G=-[V,F]-calculated after
Thus solution ambiguous  even with demand |G|->min
Re: 1372- Ambiguous solution?
Послано Sandro (USU) 28 июн 2007 15:06
And why do you think that this problem must have an unique answer? Any correct answer will be OK.
Re: 1372- Ambiguous solution?
Послано svr 28 июн 2007 15:39
Because when many solutions how  can we check
that difference with test's answer <=1E-8
Re: 1372- Ambiguous solution?
Послано Sandro (USU) 28 июн 2007 22:59
This problem has special checking program. It doesn't use the difference between your answer and jury's one.
Why so few ACs??
Послано Al.Cash 19 июн 2009 20:03
Everything needed to solve this problem is told in the first post!
And there is only simple 3D-geometry.