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back to board[censored] checkers! AC at last! -0 != 0 if program writes -0, your [censored] checker says WA#3 inspite of accuracy in 2 digits. abs(-0-0) < 0.001 ! Edited by moderator 06.04.2007 22:54 Warning for you (+) I am tired of you who offends Timus Online Judge again and again. If you continue writing your posts to this board such a way, I will just remove them completely. Edited by author 06.04.2007 22:55 Re: Warning for you (+) After your edit, observers could have an impression that I have used an abusive word. It's not true, it was word "stupid" Checker is correct. In the 3rd test your output was -1.#J and 1.#R. (-) Re: Checker is correct. In the 3rd test your output was -1.#J and 1.#R. (-) you are wrong there is fragment of my program : double Norm(double x) { // if (x>0.001) return x; // else // return 0; } ... printf("%.2lf\n",Norm(abs(...))); ... with these commets program gets WA#3 without - AC if you want, i can send you my program entirely Edited by author 07.04.2007 22:15 Checker is really correct. (+) Your WA and AC solution have are wrong both but tests are weak. You have WA after rejudge. |
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