All the operands, reserved words and operations are separated by spaces. More over, there are no spaces between label and ":" (i.e "label:", but not "label :"), and between number and its sign (i.e. "-4", but not "- 4").

then in these case:
<variable> = <varnum> + <varnum>
<variable> = <varnum> - <varnum>
<variable> = <varnum> * <varnum>
<variable> = <varnum> / <varnum>
<variable> = <varnum> % <varnum>
<variable> = <varnum> or <varnum>
<variable> = <varnum> and <varnum>
<variable> = <varnum> xor <varnum>

I read the fourth string operation, but found operation is not in the set of { +,-,*,/,%,and,or,xor}

I use case construction by the first symbol of operation: "+", "-", "*", "/", "%", "o", "a", "x". My solution would get crash otherwise. Did you assume that the operations and reserved words may be writen in upcase ("XoR", "aND", "gOTo", "pRiNT")?

I use the first character and got Accepted. like this:

if(operation[0]=='A' || operation[0]=='a')
  operation = "and";
else if(operation[0]=='X' || operation[0]=='x')
  operation = "xor";
else if(operation[0]=='O' || operation[0]=='o')
  operation = "or";


but I make the operation string to lower case and got WA.
like this:

string tmp="";
for(int i=0;i<operation.length();i++)
{
   if(operation[i]>='A' && operation[i]<='Z')
       tmp += tolower(operation[i]);
   else tmp+=operation[i];
}
operation=tmp;


But I really think if the operation string is "Xor" or "XOR" or "xOR" or "xor", the result is the same.
unless the operation string maybe something like "xoe".

Edited by author 07.03.2006 19:06

Edited by author 07.03.2006 19:06