Обсуждение @ 1294. Марсианские спутники @ Timus Online Judge

Why if ad*ac-bd*bc==0 it's impossible? In some place it is really impossible, but not for test:

Послано Fly [Yaroslavl_SU] 11 окт 2005 13:20

Why if ad*ac-bd*bc==0 it's impossible? In some place it is really impossible, but not for test:
1 2 2 1
I can select any length from interval (1,3) and it should be right answer!

Re: Why if ad*ac-bd*bc==0 it's impossible? In some place it is really impossible, but not for test:

Послано Zerolog1c [LNU] 1 дек 2005 00:11

Cause we cant calculate cos(angle) = (c^2 + d^2 - a^2 - b^2)/(2cd-2ab)

This is a cos(angle) beetween AD and AC (or BD and BC).

We'll have a division by thero..

Re: Why if ad*ac-bd*bc==0 it's impossible? In some place it is really impossible, but not for test:

Послано asd 3 фев 2006 23:01

But if
0 0 0 0
we can say that distanse = 0!!!

Problem statement says: positive integers (-)

Послано Michael Rybak (accepted@ukr.net) 10 фев 2006 16:49

Обсуждение задачи 1294. Марсианские спутники