Discuss calculation for n=4
Can you help me with mathematic calculation, I can't get 670. First I use next algorithm to count lycky integers, and he is quite good as you see:
double a[8];
int k = 0;
bool log = false;
if (n == 4)
{
do
{
a[k] = broj % 10;
broj = broj / 10;
k = k + 1;
}
while (broj != 0);
if ( a[0]+a[1] == a[2]+a[3])
log = true;
He gets result 615. After that I calculate how many 4 digit lucky numbers which begins with zero have, and I get 18. That is 615+18 = 643.
Did I miss something?
Obviosly I did, but I can't see, please help!
Re: Discuss calculation for n=4
Послано
u7gN 9 июл 2006 01:24
simply try to use function div_t, u can find it in index.