1000=1^3+0^3+0^3+0^3=1
1=1^3=1
IF THE DISTANCE BETWEEN TWO POINTS = 1 THAT FOLLOWING TOO WILL BE 1.
USE BREAK

It is wrong.
"Oh, by the way! The value of SMK is always divisible by 3. It’s normal for Martians – all their numbers are divisible by 3."

 On another if the previous number is equal to next that break

f(153)=1^3+5^3+3^3=1+125+27=153
=))

That's really so! :) Thank you! I've got AC!

Its my solution:
[code deleted]

Edited by author 21.06.2007 01:35

Edited by moderator 06.12.2019 20:30

Your prog get AC, but
look at this test:
1
33333 313 1
log of my prog:
  2)   55
  3)  250
  4)  133
  5)   55
  6)  250
  7)  133
  8)   55
  9)  250
 10)  133
 11)   55
 12)  250
 13)  133
 14)   55
 15)  250
 16)  133
 17)   55
 18)  250
 19)  133
 20)   55
 21)  250
 22)  133
 23)   55
 24)  250
 25)  133
 26)   55
 27)  250
-----
there is period! And you never get dist[j]==dist[j-1]
And your prog get TLE on my test:
       ||| 33333
1)     ||| 33333 313 1
2)     ||| 33333 313 1
3)     ||| 33333 313 1
4)     ||| 33333 313 1
5)     ||| 33333 313 1
i)     ||| 33333 313 1
33333) ||| 33333 313 1

But there is no such tests => AC. =)

[code deleted]

Edited by author 02.12.2011 18:57

Edited by moderator 06.12.2019 20:31

313 isn't divisible by 3.