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вернуться в форумWA on #3, help please, MLE on #12 var g:array[1..1000,1..1000] of Boolean; i,j,n,a,k,s:smallint; procedure find(i:smallint); var j:smallint; begin for j:=n downto 1 do if g[i,j] then begin g[i,j]:=false; find(j) end; if s<>0 then writeln(s,' ',i); s:=i; end; begin assign(input,''); reset(input); readln(n,a); for i:=1 to n do for j:=1 to n do begin read(k); g[i,j]:=(k=0) and (i<>j) end; close(input); s:=0; find(a); end. If I put s in memory and write it in reverse order I get MLE on test 12: var g:array[1..1000,1..1000] of Boolean; i,j,n,a,k,st:smallint; s:array[1..32000] of smallint; procedure find(i:smallint); var j:smallint; begin for j:=n downto 1 do if g[i][j] then begin g[i][j]:=false; find(j) end; inc(st); s[st]:=i end; begin assign(input,''); reset(input); readln(n,a); for i:=1 to n do for j:=1 to n do begin read(k); g[i][j]:=(k=0) and (i<>j) end; close(input); st:=0; find(a); for i:=st-1 downto 1 do writeln(s[i+1],' ',s[i]); end. Please help me solve either of this two problems. Re: WA on #3, help please, MLE on #12 There are two way to accept it: 1. Use stack instead of recursion. 2. Use recursion without variable "j". In all cases you can use array "st" and don't worry about memory limit. Re: WA on #3, help please, MLE on #12 you can use dynamic lists for the graph instead of that bool matrix... |
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