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| Show all threads Hide all threads Show all messages Hide all messages | | It's very beatyfull problem. Thanks | KostyaRychkov`~ | 2105. Alice and Bob are on Bikes | 10 Aug 2026 11:10 | 2 | | | If one of players is waiting, meeting still takes place | bidzilya | 2105. Alice and Bob are on Bikes | 7 Aug 2026 22:15 | 1 | Test case is mentioned in other topic
10 10 10 10
1
1 0 10
Answer is 10 | | WA #2 | Marginean Ciprian | 2105. Alice and Bob are on Bikes | 15 Nov 2020 21:07 | 2 | WA #2 Marginean Ciprian 14 Nov 2018 22:19 Can you please give me a test for my code? For WA#2 you have to check if Alice/Bob are waiting exact amount di. I tried case when di=0, and noticed my code waits 1 time, instead of waiting for 0. | | To admin, please, fix the statement. | coder | 2105. Alice and Bob are on Bikes | 18 Apr 2017 12:26 | 2 | << When they “meet” (i.e., at some moment they are in the same point as in the PREVIOUS WERE NOT), they joyfully exclaim (“Oh, Bob!” or “Oh, Alice!” respectively).>>
Let this test:
L = 10 T = 10 va = 10 vb = 10
n = 1 type = 1 t[1] = 0, d[1] = 10.
Alice and Bob "meet" 10 times at the SAME point, so answer should be 1.
But, AC solution gives 10. >> at some moment they are in the same point
>> at some moment
there are different moments for their meeting | | Что за 4 тест???? | simoncatcity | 2105. Alice and Bob are on Bikes | 9 Mar 2017 14:32 | 1 | Что за 4 тест??? не могу понять, где что неправильно... | | Correct answer? | szczepi | 2105. Alice and Bob are on Bikes | 8 Dec 2016 19:27 | 2 | What answer should be for given test?
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