Что означает отношения квадрата и куба и что за число n

[code deleted]

Edited by moderator 27.07.2023 17:22

//#pragma GCC optimize("Ofast,no-stack-protector")
//#pragma GCC target("avx")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace __gnu_pbds;
using namespace std;

#define re return
#define pb push_back
#define eb emplace_back
#define all(x) (x).begin(), (x).end()
#define fi first
#define se second
#define sqrt(x) sqrt(abs(x))
#define mp make_pair
#define pi (3.14159265358979323846264338327950288419716939937510)
#define fo(i, n) for(int i = 0; i < n; ++i)
#define ro(i, n) for(int i = n - 1; i >= 0; --i)
#define unique(v) v.resize(unique(all(v)) - v.begin())

template <class T> T abs (T x) { re x > 0 ? x : -x; }
template <class T> T sqr (T x) { re x * x; }
template <class T> T gcd (T a, T b) { re a ? gcd (b % a, a) : b; }
template <class T> int sgn (T x) { re x > 0 ? 1 : (x < 0 ? -1 : 0); }

typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<string> vs;
typedef double D;
typedef long double ld;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef unsigned long long ull;
typedef tree <pair<int, char>, null_type, less<pair<int, char>>, rb_tree_tag, tree_order_statistics_node_update> _tree;

map <int, int> m;

void get (int x) {
    for (int i = 2, end = sqrt(x) + 1; i <= end; ++i) {
        if (x % i == 0) {
            m[i]++;
            x /= i;
            if (x > 1) get(x);
            re;
        }
    }
    if (x > 1) m[x]++;
}

int main() {
    ull n, _m = 1, k = 1;
    cin >> n;
    if (n == 1) {
        cout << "1\n1\n";
        re 0;
    }
    get(n);
    for (auto j : m) {
        //cout << j.fi << ' '<< j.se << endl;
        if (j.se & 1) {
            k *= j.fi;
            j.se += 3;
        }
        j.se /= 2;
        fo(i, j.se) _m *= j.fi;
    }
    cout << _m << '\n' << k << endl;
    re 0;
}

It's very easy problem, but many people don't understand how to solve it ... :)

7 lines :

#include <iostream>
using namespace std;
int main(){
unsigned long long N;
cin >> N;
cout << N*N << endl << N;
return 0; }

#include<iostream>
#include<stdlib.h>
#include<math.h>
using namespace std;
int main()
{long double n;
    long long int m,i;
    cin>>m;

    for(i=1;i<10000000000000000000;i++)
    {
        n=sqrt(i*i*i*m);
        if(n==floor(n+0.5))
        {    cout<<n<<endl<<i;break;}
    }
    fflush(stdin);
    getchar();
return 0;}

#include<iostream>
using namespace std;
int main()
{       double n;
    long long int m,i;
    cin>>m;

    for(i=1;i<10000000000000000000;i++)
    {
        n=sqrt(i*i*i*m);
        if(n==floor(n+0.5))
        {    cout<<n<<endl<<i;
                        break;
                 }
    }
    fflush(stdin);
    getchar();
        return 0;
}

#include <stdio.h>

int main(){
    long long int t;
    scanf("%lld", &t);
    printf("%lld\n%lld", t*t, t);
    return 0;
}

AC with MS VC, but WA 1 with GCC.
Can anybody explain me what's wrong with my code?

you must print n^2 and n.

Why n = 18; m = 12, k = 2;

When n = 18; m = 324, k = 18;

Edited by author 21.04.2011 20:52

The obvious solution is too simple.
You should ask for the smallest numbers. That solution is also easy enough, so it shouldn't be a problem for most people.

Anyway, maybe the purpose of this problem is to teach people to use __int64. In that case simpler is better :)

Edited by author 22.02.2009 21:50

Please give the test

"324 18" - wrong answer
"324\n18" - accepted

Judges, is it normal?

And, it's all that I've to speak to you.

** sorry for my bad english.. :D

#include <iostream>
#include <math.h>
using namespace std;

unsigned long long  n,b,c,k,m;
long double f,i;
int main ()
{
   cin >>n;
   b=2;
   if (modf(sqrt((double)n),&i)==0) {cout <<(unsigned long long)sqrt((double)n)<<"\n"; cout <<"1"<<"\n";}
   else
   {
   for ( ;b<=n;b++)
   {
      f=modfl(sqrt((long double)n*(double)(b*b*b)),&i);
      if (f==0) break;
   }
    m=(unsigned long long )sqrt((long double)n*(double)(b*b*b));
   cout <<m<<"\n";
   cout <<b<<"\n";
   }
   return 0;
}

you can write any numbers which can answer the condition but didn't smallest

why get 'ac'  used  ""pascl""

var n:int64;

begin

  readln(n);

  writeln(n*n);

  writeln(n);

end.
---------------------------------
but:
 #include<stdio.h>
int main()
{  unsigned  long long n;
               scanf("%lld",&n);
               printf("%lld\n",n*n);
               printf("%lld\n",n);
 return 0;
}

who could tell me when i use "c",get "wa"?   i am confused;

help me++++++++