cost, fun1, fun2 = map(int,input().split())
fri, flat2 = [], []
for i in range(int(input())):
        fri.append(list(map(int,input().split())))

temp1, temp2 = [-1,-1], [-1, -1, -1] #веселье, квартрира, сосед
for i in range(int(input())) :
        a, b, c = map(int,input().split())
        if a == 2 :
                flat2.append([b,c,i+1]) # стоимость, веселье, номер
        if fun1 + c > temp1[0] and cost >= b :
                temp1 = [fun1+c, i+1]

for i in range(len(flat2)) :
        b, c, k  = flat2[i][0], flat2[i][1], flat2[i][2]
        for j in range(len(fri)) :
                if fri[j][0] >= b/2 and cost >= b/2 and fun2+fri[j][1]+c > temp2[0] :
                        temp2 = [fun2+fri[j][1]+c, j+1, k]

if temp1[0] == -1 and temp2[0] == -1 :
        print('Forget about apartments. Live in the dormitory.')
elif temp1[0] > temp2[0] :
        print('You should rent the apartment #'+str(temp1[1])+ ' alone.')
else :
        print('You should rent the apartment #'+str(temp2[2])+' with the friend #'+str(temp2[1])+'.')

Edited by author 16.09.2016 21:53

Try to reread the task. I've been adding up wrong numbers together because of the misunderstanding.

Also, try tests from "If you have WA6"

Edited by author 25.10.2017 07:16

98000 3334 3334
1
25000 3333
3
1 97999 1
2 30000 1
2 25000 1

Answer - You should rent the apartment #1 alone. or You should rent the apartment #2 alone. or You should rent the apartment #3 alone.

21111 1111 7777
5
1111 7777
10000 6556
20000 3131
80000 2
76400 1
4
1 21110 6000
1 21111 6665
2 21111 1220
2 1110 0

Answer - You should rent the apartment #3 alone.

1001 1001 1001
1
1001 1
1
2 1001 1

Answer - You should rent the apartment #1 alone.

I hope it can help. My program, which got WA 6, failed on this tests.

Please, give me some tests. I can't understand why i get WA4.

Chto za xren Test 5?
Does anybody know what the hell is Test 5?

Try this test:
1 0 0
0
1
1 1 0

Answer: You should rent the apartment #1 alone.

Please give me some tests

this is my code:
#include <iostream>
using namespace std;

int main()
{
    long sj,prj1,prj2,n,k,sd[256],prd[256],kom[256],sh[256],prh[256];
    cin>>sj>>prj1>>prj2>>n;
    for(int i=0;i<n;i++)
    cin>>sd[i]>>prd[i];
    cin>>k;
    for(int i=0;i<k;i++)
    cin>>kom[i]>>sh[i]>>prh[i];

    long max=-1,nh=0,nd=0;

    for(int i=0;i<k;i++)
        if(kom[i]==1) { if(sh[i]<=sj&&(prj1+prh[i]>max)) {max=prj1+prh[i];nh=i+1;nd=0;}}
        else {
        if(sh[i]<=sj&&(prj2+prh[i]>max)) {max=prj2+prh[i];nh=i+1;nd=0;}
        for(int j=0;j<n;j++)
        if(sh[i]<=int(double(sj)/2.0+double(sd[j])/2.0)&&(prh[i]+prd[j]>max)) {max=prh[i]+prd[j];nh=i+1;nd=j+1;}
        }

    if(nd==0)
    {if(nh==0) cout<<"Forget about apartments. Live in the dormitory."<<endl;
    else cout<<"You should rent the apartment #"<<nh<<" alone."<<endl;
    } else cout<<"You should rent the apartment #"<<nh<<" with the friend #"<<nd<<"."<<endl;




    return 0;
}

Edited by author 29.11.2014 15:08

Если двухкомнатная квартира стоит нечётную стоимость, как делится её цена?

Give me some tests please