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Общий форумyyll wrong constant of earth [1] // Задача 1030. Титаник 15 сен 2022 08:39 diameter of 6875 miles (/ 2 = 3437.5)??? the mean radius of earth is 6371.0 km (3958.8 miles) Solver Re: wrong constant of earth // Задача 1030. Титаник 14 июл 2026 07:11 Nautical miles are different Solver On WA8 // Задача 1569. Сети в Исети 14 июл 2026 06:14 You have to check all edges between centroids, not just arbitrary one. Although it leads to O(N^4) due to N^2 BFSes on cliques, early cutoff on max-dist from roots vs. current result makes it almost O(N^3). AC 0.046 sec Solver Notice // Задача 1569. Сети в Исети 13 июл 2026 11:04 You may output edge nodes in any order (1 2) or (2 1) checker accepts that Last_Vikings Who know how the 2nd test looks like?? [18] // Задача 1546. Сортировка по-японски 21 апр 2007 14:18 We cannot imagine the test where our prog will give wrong answer! Donat +1 for question (-) // Задача 1546. Сортировка по-японски 21 апр 2007 17:11 I want to find out too Mingfei Li Re: Who know how the 2nd test looks like?? [6] // Задача 1546. Сортировка по-японски 21 апр 2007 17:11 I wonder too, always wa on test 2 Alias aka Alexander Prudaev Re: Who know how the 2nd test looks like?? [5] // Задача 1546. Сортировка по-японски 24 апр 2007 19:28 1w1 01w01a Edited by author 24.04.2007 19:29 Mace(Lviv Polytechniс NU) Re: Who know how the 2nd test looks like?? [4] // Задача 1546. Сортировка по-японски 25 апр 2007 19:41 No, its not 2nd test. My prog correctly process it, but stil WA2. Alias aka Alexander Prudaev Re: Who know how the 2nd test looks like?? [3] // Задача 1546. Сортировка по-японски 25 апр 2007 19:59 sorted: 01w01 01w1 01w01a z000 z00 z00p z0p and one more 0 0p 01 1 1p Edited by author 25.04.2007 20:03 Mace(Lviv Polytechniс NU) Re: Who know how the 2nd test looks like?? [2] // Задача 1546. Сортировка по-японски 26 апр 2007 01:09 Yeap, that`s it... Thx. Alexander Kouprin Re: Who know how the 2nd test looks like?? [1] // Задача 1546. Сортировка по-японски 30 апр 2007 10:18 Try this test: z0p z00pp z0pp z00pp00 z000pp01 z00pp01 z0pp01 z001pp00 z01pp00 z1pp00000 z01pp01 z1pp001pp0 z1pp01pp000 I get WA#2 too. MishaRash Re: Who know how the 2nd test looks like?? // Задача 1546. Сортировка по-японски 19 авг 2015 23:33 Huge thanks to Alexander Kouprin, after running his test and solving the problem I got accepted. Test from Alexander Georgiev also helped me a lot. By the way, my program gives other output for some test from this thread. Here they are: abc00125a abc0125a abc00125b abc0125b abc000000000000000000000125a abc00000000000000000000125a abc0012000000000000000000000000005b abc012000000000000000000000000005b These tests have almost broken my mind while I have been thinking why they are correct and I'm happy that I do not have to fix my program because of them. Petr Huggy (Pskov) Re: Who know how the 2nd test looks like?? [3] // Задача 1546. Сортировка по-японски 2 май 2007 12:29 Zeroes matters only if strings are equal. Try this: abc0125a abc00125a abc00125b abc0125b bor2com (SSU) Re: Who know how the 2nd test looks like?? [2] // Задача 1546. Сортировка по-японски 11 фев 2008 16:59 Petr Huggy (Pskov) писал(a) 2 мая 2007 12:29 Try this: I suppose the last test by Peter Huggy is the most similar to second testabc0125a abc00125a abc00125b abc0125b but after all this tests WA6 tec Re: Who know how the 2nd test looks like?? [1] // Задача 1546. Сортировка по-японски 7 мар 2008 22:04 Try this: abc00000000000000000000125a abc000000000000000000000125a abc0012000000000000000000000000005b abc012000000000000000000000000005b bor2com (SSU) писал(a) 11 февраля 2008 16:59 I suppose the last test by Peter Huggy is the most similar to second test but after all this tests WA6 Denis Koshman Re: Who know how the 2nd test looks like?? // Задача 1546. Сортировка по-японски 14 июл 2008 20:28 Got AC, thanks to Alias tests :) espr1t Re: Who know how the 2nd test looks like?? [5] // Задача 1546. Сортировка по-японски 29 сен 2008 18:56 You can also try: 0000000 000 (Already sorted) IgorKoval [PskovSU] Re: Who know how the 2nd test looks like?? [1] // Задача 1546. Сортировка по-японски 14 янв 2012 19:36 Thank to everybody! =) xDEMONx [Perm SU] Who know how the 2nd test looks like?? // Задача 1546. Сортировка по-японски 10 июн 2014 01:19 Your program must return for these tests next results (alredy sorted): 1) 000 00 0 2) 00 0 000a 3) 00a000 00a0 mouse_wireless2 Re: Who know how the 2nd test looks like?? [2] // Задача 1546. Сортировка по-японски 3 янв 2018 19:21 I don't understand this. Why is 0000000 smaller than 000? What's the logic behind it? morbidel Re: Who know how the 2nd test looks like?? [1] // Задача 1546. Сортировка по-японски 12 янв 2021 22:29 Edited by author 12.01.2021 22:30 Solver Re: Who know how the 2nd test looks like?? // Задача 1546. Сортировка по-японски 12 июл 2026 08:40 I think logic behind it is when strings are equal on "japanese" interchanging alpha-numeric sequences, then the whole strings are compared, so that puts 001 before 01 and 002 before 02. Only 000 and 00 stand aside, so it's a matter of consistency with other numeric values. Or think of it the other way - append something like '~' (ASCII 126) to the end of the sting, that will put 001~ before 01~ and 000~ before 00~ bor2com (SSU) what mean "lexicographically first compatible pair" ? [3] // Задача 1530. Ones and Zeroes 11 дек 2007 20:39 I try to output zeros in this case, but seems like I'm wrong please show me some example for example for this case 2 11 11 Edited by author 11.12.2007 21:50 winger Re: what mean "lexicographically first compatible pair" ? // Задача 1530. Ones and Zeroes 13 дек 2007 12:14 This test is incorrect Denis Koshman Re: what mean "lexicographically first compatible pair" ? [1] // Задача 1530. Ones and Zeroes 14 июл 2008 01:40 This test is correct, and the answer should be 00 00 Solver Re: what mean "lexicographically first compatible pair" ? // Задача 1530. Ones and Zeroes 12 июл 2026 04:21 The test is correct, original sequences do not need to be compatible Yosif Yosifov A hint ? [9] // Задача 1530. Ones and Zeroes 20 фев 2007 01:33 Can someone give me a little hint, please ? KirillB(Arkhangelsk - PomorSU) Re: A hint ? [8] // Задача 1530. Ones and Zeroes 20 фев 2007 01:44 make 2 sequences (s1 and s2) such that s1[i]+s2[i]<>2 Ivan Ivanov Re: A hint ? [7] // Задача 1530. Ones and Zeroes 20 фев 2007 12:28 My solution is based on a greedy approach. Yosif Yosifov Re: A hint ? [6] // Задача 1530. Ones and Zeroes 21 фев 2007 02:38 Thank you both ! :-) svr Re: A hint ? [5] // Задача 1530. Ones and Zeroes 21 фев 2007 09:04 I think that an algorithm has many special cases. Main rool:to correct firstly s2[i] from 1 to 0 in pair s1[i]=1 and s2[i]=1 diminishing B but have pair 0, 0 in older position correcting it to 0, 1 for final increasing lexiographicly of B Who can find all cases he solve the problem svr Re: A hint ? [2] // Задача 1530. Ones and Zeroes 21 фев 2007 13:57 After getting AC i have counted 6 cases next tests correspong each of cases 4 1011 0011 1011 0100 4 1010 0111 1011 0000 4 1011 0110 1100 0000 4 1111 0101 0000 0000 4 1010 0101 1011 0000 4 1011 0100 1100 0000 Edited by author 21.02.2007 13:58 Soul Reaver Re: A hint ? [1] // Задача 1530. Ones and Zeroes 20 мар 2007 01:04 My program successfully passed all of your test cases, but I still WA3... What can it be??? svr Re: A hint ? // Задача 1530. Ones and Zeroes 20 мар 2007 08:26 You are need in additional tests Best if you will create them yourself Denis Koshman Re: A hint ? [1] // Задача 1530. Ones and Zeroes 14 июл 2008 01:47 I have only 3 cases 1) attempt to build a >b 2) attempt to build a+1 0 3) build 0 0 Solver Re: A hint ? // Задача 1530. Ones and Zeroes 12 июл 2026 04:19 A + B = A XOR B iff there is no carry, or in other words A AND B = 0 So the algo is simple Find leftmost x such that p[x]=q[x]=1. if none, assume x=n+1. Find rightmost y to the left of x such that p[y]=q[y]=0. If none, output p+1, 0 (p+1 may become 0). Otherwise set q[y]=1, and q[y+1..n]=0 Edited by author 12.07.2026 04:38 Keworker `~ Overrated [1] // Задача 1154. Сражение магов 14 авг 2024 13:02 This task has some problems with accurancy, but 878 is too big rating for it. Solver Re: Overrated // Задача 1154. Сражение магов 11 июл 2026 09:16 Agreed. On precision - performing multiplications before division and comparing at 1e-8 works. Lebedev_Nicolay[Ivanovo SPU] Need Clarification! [3] // Задача 1277. Cops and Thieves 24 июл 2009 21:19 Can anybody expalain me this problem? I think that in both samples answer is YES, because all vertices are next to refuge or to museum. Lebedev_Nicolay[Ivanovo SPU] Re: Need Clarification! [2] // Задача 1277. Cops and Thieves 2 фев 2010 00:31 At last I've solved it. what about solution: 1) for maxflow use RelabelToFront 2) WA 36 : try this test 5 3 2 2 3 1 2 3 1 2 2 3 answer: NO 3) WA 38: test 5 3 2 2 2 1 2 3 1 2 2 3 answer: NO Edric Mao Re: Need Clarification! [1] // Задача 1277. Cops and Thieves 5 ноя 2011 18:44 Thanks a lot Solver Re: Need Clarification! // Задача 1277. Cops and Thieves 11 июл 2026 07:27 Thanks frost_nova WA#6 [6] // Задача 1547. Перебор паролей 12 май 2007 03:36 Dmytro Dziuma (DixonD) [Lviv NU] Re: WA#6 [5] // Задача 1547. Перебор паролей 8 мар 2008 19:26 Try test 2 27 morbidel Re: WA#6 [4] // Задача 1547. Перебор паролей 19 мар 2008 18:51 I got also WA at #6 and made some tests on the input. It seems that the line if (N == 34 && M == 49) while (1); got TLE (6) so the test is 34 49. My answer to this test is a-niaacgvtxwdouniwkovyjlpaaaerlqkyo niaacgvtxwdouniwkovyjlpaaaerlqkyp-aaarepihxnlfzhjsqrzpokzcbpyfypjwat aaarepihxnlfzhjsqrzpokzcbpyfypjwau-aqaaaaaaaaiiovpgvvmsnhsbbrtjgmuqbw aqaaaaaaaaiiovpgvvmsnhsbbrtjgmuqbx-bejdhnxluhaaainzrkuauccrqbastmtecb bejdhnxluhaaainzrkuauccrqbastmtecc-bssejrqozpnkflharcuholuvjdvwynyaaa bssejrqozpnkflharcuholuvjdvwynyaaa-chbflvjseyarrdiqpnyomjekfzqbtgnktz chbflvjseyarrdiqpnyomjekfzqbtgnkua-cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkm cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkn-djthqcvyppbgonlwmkhcidxnzrelirsgaz djthqcvyppbgonlwmkhcidxnzrelirsgba-dycisgpbuxooafnmkvljgbhcwmyqdkhqrm dycisgpbuxooafnmkvljgbhcwmyqdkhqrn-emljukifaapbxjvblttjroekmwfuxvlxyx emljukifaapbxjvblttjroekmwfuxvlxyy-faukwobifopcxpqshrtxbwaaaxbkkpmjnr faukwobifopcxpqshrtxbwaaaxbkkpmjns-fpdlyrulkxckjhsigcydztjvnaayrhdnnv fpdlyrulkxckjhsigcydztjvnaayrhdnnw-gdmnachtlazghlttujryytfbucbeeqsbil gdmnachtlazghlttujryytfbucbeeqsbim-grvoczgrvoczgrvoczgrvoczgrvoczgrvv grvoczgrvoczgrvoczgrvoczgrvoczgrvw-hgepfczvawqgsjxebkkytlmodnpsxrwcmh hgepfczvawqgsjxebkkytlmodnpsxrwcmi-hunqhgsygfdoebytzvpfriwdajjxsklnct hunqhgsygfdoebytzvpfriwdajjxsklncu-iiwrjkmblnqvpuajygtmpgfrxfecndaxtf iiwrjkmblnqvpuajygtmpgfrxfecndaxtg-ixfslofeqwedbmbzwrxtndpguayhhvqijr ixfslofeqwedbmbzwrxtndpguayhhvqijs-jlotnryhwerknedpvdcalayvqwsmcoftaa jlotnryhwerknedpvdcalayvqwsmcoftaa-jzxupvrlbnerywfftoghiyiknsmqxgvdqp jzxupvrlbnerywfftoghiyiknsmqxgvdqq-kogvrzkogvrzkogvrzkogvrzkogvrzkohb kogvrzkogvrzkogvrzkogvrzkogvrzkohc-lcpwuddrmefgwgilqkovetbohkbamrzyxn lcpwuddrmefgwgilqkovetbohkbamrzyxo-lqyxwgwurmsohykbovtccqldefvfhkpjnz lqyxwgwurmsohykbovtccqldefvfhkpjoa-mfhyykpxwvfvtqlrngxjanusbbpkcdeuel mfhyykpxwvfvtqlrngxjanusbbpkcdeuem-mtraaaaaaadyagcaylnbwefjfiwhlkxzyt mtraaaaaaadyagcaylnbwefjfiwhlkxzyu-niaaaaaamqmtnchcwhigpdmsazucrszvdb niaaaaaamqmtnchcwhigpdmsazucrszvdc-nwjcevvhmutscsqniokdufxkroxymgzaaa nwjcevvhmutscsqniokdufxkroxymgzaaa-oksdgzoksdgzoksdgzoksdgzoksdgzoksh oksdgzoksdgzoksdgzoksdgzoksdgzoksi-ozbejdhnxluhaabhlcxuvdfatyrziklvtv ozbejdhnxluhaabhlcxuvdfatyrziklvtw-pnkflharcuholuvjdvwynyaabjmfvzjyxn pnkflharcuholuvjdvwynyaabjmfvzjyxo-qbtgnktuicuvxmwzchbflvjseyarrdiqpr qbtgnktuicuvxmwzchbflvjseyarrdiqps-qqchpomxnlidjeypacedivahvrcqaaaaaa qqchpomxnlidjeypacedivahvrcqaaaaaa-relirsgastvkuxaezdjthqcvyppbgonlwp relirsgastvkuxaezdjthqcvyppbgonlwq-rsujtvzdycisgpbuxooafnmkvljgbhcwnb rsujtvzdycisgpbuxooafnmkvljgbhcwnc-shdkvzshdkvzshdkvzshdkvzshdkvzshdn shdkvzshdkvzshdkvzshdkvzshdkvzshdo-svmlydlkitjhdzfaukwobifopcxpqshrtz svmlydlkitjhdzfaukwobifopcxpqshrua-tjvnacjothflsugpqhyezmsbiabaabensx tjvnacjothflsugpqhyezmsbiabaabensy-tyeockxqtkjwbjigrhfbxcysiulzgdmnax tyeockxqtkjwbjigrhfbxcysiulzgdmnay-umnpeoqtysxdnbjwpsjivaihfqgeawbxrj umnpeoqtysxdnbjwpsjivaihfqgeawbxrk-vawqgsjxebkkytlmodnpsxrwcmaivorihv vawqgsjxebkkytlmodnpsxrwcmaivorihw-vpfriwdajjxsklncmorwqvbkzhunqhgsyh vpfriwdajjxsklncmorwqvbkzhunqhgsyi-wdoskzwdoskzwdoskzwdoskzwdoskzwdot wdoskzwdoskzwdoskzwdoskzwdoskzwdou-wrxtndpguayhhvqijlabeukemqvwvdoaaa wrxtndpguayhhvqijlabeukemqvwvdoaaa-xgguphijzjlotnryhwerknedpvdcaaaaud xgguphijzjlotnryhwerknedpvdcaaaaue-xupvrlbnerywfftoghiyiknsmqxgvdqjmd xupvrlbnerywfftoghiyiknsmqxgvdqjme-yiywtouqkamdqxveesnfghxhjmrlpwfucp yiywtouqkamdqxveesnfghxhjmrlpwfucq-yxhxvsntpizlcpwuddrmefgwgilqkovetb yxhxvsntpizlcpwuddrmefgwgilqkovetc-zlqyxwgwurmsohykbovtccqldefvfhkpjn zlqyxwgwurmsohykbovtccqldefvfhkpjo-zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz Can anyone write the correct answer? Thank you Edited by author 19.03.2008 18:53 morbidel Re: WA#6 [1] // Задача 1547. Перебор паролей 19 мар 2008 19:26 I don't understant what's wrong, here are the number of pieces each processor has: 34 49 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683277 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 27285448088939550474430463423979178157730683276 (26^34) % M = 10 so I distributed the 10 remaining strings on the first processors, according to the sample test (when the remainder was 2) Any hint? morbidel Re: WA#6 // Задача 1547. Перебор паролей 22 мар 2008 04:20 solved! 'bssejrqozpnkflharcuholuvjdvwynyaaa' on processor 5 and 6 is obviously wrong IgorKoval [PskovSU] Re: WA#6 [1] // Задача 1547. Перебор паролей 15 мар 2012 23:34 input: 34 49 output: a-niabcscehmgkraoxkdfwwinvutdtrojpm niabcscehmgkraoxkdfwwinvutdtrojpn-abrbdglfjpznwjcevvhmutscsqniokdufz abrbdglfjpznwjcevvhmutscsqniokduga-aqacfkeioymvibduugltsrbrpmhnjctewm aqacfkeioymvibduugltsrbrpmhnjctewn-bejdhnxluhacttfksrqaqolgmibsdvipmz bejdhnxluhacttfksrqaqolgmibsdvipna-bssejrqozpnkflharcuholuvjdvwynyadm bssejrqozpnkflharcuholuvjdvwynyadn-chbflvjseyarrdiqpnyomjekfzqbtgnktz chbflvjseyarrdiqpnyomjekfzqbtgnkua-cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkm cvkgnzcvkgnzcvkgnzcvkgnzcvkgnzcvkn-djthqcvyppbgonlwmkhcidxnzrelirsgaz djthqcvyppbgonlwmkhcidxnzrelirsgba-dycisgpbuxooafnmkvljgbhcwmyqdkhqrm dycisgpbuxooafnmkvljgbhcwmyqdkhqrn-emljukifagbvlxpcjgpqdyqrtisuycxbhz emljukifagbvlxpcjgpqdyqrtisuycxbia-faukwobifopcxpqshrtxbwagqemzsvmlyl faukwobifopcxpqshrtxbwagqemzsvmlym-fpdlyrulkxckjhsigcydztjvnahenobwox fpdlyrulkxckjhsigcydztjvnahenobwoy-gdmnavnoqfpruztyeockxqtkjwbjigrhfj gdmnavnoqfpruztyeockxqtkjwbjigrhfk-grvoczgrvoczgrvoczgrvoczgrvoczgrvv grvoczgrvoczgrvoczgrvoczgrvoczgrvw-hgepfczvawqgsjxebkkytlmodnpsxrwcmh hgepfczvawqgsjxebkkytlmodnpsxrwcmi-hunqhgsygfdoebytzvpfriwdajjxsklnct hunqhgsygfdoebytzvpfriwdajjxsklncu-iiwrjkmblnqvpuajygtmpgfrxfecndaxtf iiwrjkmblnqvpuajygtmpgfrxfecndaxtg-ixfslofeqwedbmbzwrxtndpguayhhvqijr ixfslofeqwedbmbzwrxtndpguayhhvqijs-jlotnryhwerknedpvdcalayvqwsmcoftad jlotnryhwerknedpvdcalayvqwsmcoftae-jzxupvrlbnerywfftoghiyiknsmqxgvdqp jzxupvrlbnerywfftoghiyiknsmqxgvdqq-kogvrzkogvrzkogvrzkogvrzkogvrzkohb kogvrzkogvrzkogvrzkogvrzkogvrzkohc-lcpwuddrmefgwgilqkovetbohkbamrzyxn lcpwuddrmefgwgilqkovetbohkbamrzyxo-lqyxwgwurmsohykbovtccqldefvfhkpjnz lqyxwgwurmsohykbovtccqldefvfhkpjoa-mfhyykpxwvfvtqlrngxjanusbbpkcdeuel mfhyykpxwvfvtqlrngxjanusbbpkcdeuem-mtraaojbcdtdfinhlsbpylegxxjowvueux mtraaojbcdtdfinhlsbpylegxxjowvueuy-niabcscehmgkraoxkdfwwinvutdtrojplj niabcscehmgkraoxkdfwwinvutdtrojplk-nwjcevvhmutscsqniokdufxkroxymgzabv nwjcevvhmutscsqniokdufxkroxymgzabw-oksdgzoksdgzoksdgzoksdgzoksdgzoksh oksdgzoksdgzoksdgzoksdgzoksdgzoksi-ozbejdhnxluhacttfksrqaqolgmibsdvit ozbejdhnxluhacttfksrqaqolgmibsdviu-pnkflharcuholuvjdvwynyadicgmwktfzf pnkflharcuholuvjdvwynyadicgmwktfzg-qbtgnktuicuvxmwzchbflvjseyarrdiqpr qbtgnktuicuvxmwzchbflvjseyarrdiqps-qqchpomxnlidjeypasfmjsthbtuwlvybgd qqchpomxnlidjeypasfmjsthbtuwlvybge-relirsgastvkuxaezdjthqcvyppbgonlwp relirsgastvkuxaezdjthqcvyppbgonlwq-rsujtvzdycisgpbuxooafnmkvljgbhcwnb rsujtvzdycisgpbuxooafnmkvljgbhcwnc-shdkvzshdkvzshdkvzshdkvzshdkvzshdn shdkvzshdkvzshdkvzshdkvzshdkvzshdo-svmlydlkitjhdzfaukwobifopcxpqshrtz svmlydlkitjhdzfaukwobifopcxpqshrua-tjvnahenobwoprgqswauzfpdlyrulkxckl tjvnahenobwoprgqswauzfpdlyrulkxckm-tyeockxqtkjwbjigrhfbxcysiulzgdmnax tyeockxqtkjwbjigrhfbxcysiulzgdmnay-umnpeoqtysxdnbjwpsjivaihfqgeawbxrj umnpeoqtysxdnbjwpsjivaihfqgeawbxrk-vawqgsjxebkkytlmodnpsxrwcmaivorihv vawqgsjxebkkytlmodnpsxrwcmaivorihw-vpfriwdajjxsklncmorwqvbkzhunqhgsyh vpfriwdajjxsklncmorwqvbkzhunqhgsyi-wdoskzwdoskzwdoskzwdoskzwdoskzwdot wdoskzwdoskzwdoskzwdoskzwdoskzwdou-wrxtndpguayhhvqijlakmpuoszixfsloff wrxtndpguayhhvqijlakmpuoszixfslofg-xgguphijzjlotnryhwerknedpvdcalayvr xgguphijzjlotnryhwerknedpvdcalayvs-xupvrlbnerywfftoghiyiknsmqxgvdqjmd xupvrlbnerywfftoghiyiknsmqxgvdqjme-yiywtouqkamdqxveesnfghxhjmrlpwfucp yiywtouqkamdqxveesnfghxhjmrlpwfucq-yxhxvsntpizlcpwuddrmefgwgilqkovetb yxhxvsntpizlcpwuddrmefgwgilqkovetc-zlqyxwgwurmsohykbovtccqldefvfhkpjn zlqyxwgwurmsohykbovtccqldefvfhkpjo-zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz Solver Re: WA#6 // Задача 1547. Перебор паролей 10 июл 2026 01:22 Thanks for the test :) I solved it using base-26 long arithmetics, but forgot to prepend leading zeroes (leading 'a'), so could output "brg" instead of "aabrg" Nikita Mogilevets Possible way to solve it (long arithmetic ) [1] // Задача 1547. Перебор паролей 14 май 2017 22:02 Calculate powers of 26 and prefix sums of powers of 26. Calculate ranges by integer division. Calculate each password from left to right like you would calculate k-permutation using factorial digit system. Solver Re: Possible way to solve it (long arithmetic ) // Задача 1547. Перебор паролей 10 июл 2026 01:06 Base-26 arithmetics simplifies things a lot here :) Denis Koshman What if pawns eats bishop? [2] // Задача 1398. Слон и пешка 6 авг 2008 06:16 It's not clear if black player can continue movement or not after eating white bishop. Fyodor Menshikov Re: What if pawns eats bishop? [1] // Задача 1398. Слон и пешка 22 апр 2009 19:11 Bishop moves first, so if at first pawn can capture bishop it does not matter. On the next moves bishop can avoid such positions where pawn can capture it. Solver Re: What if pawns eats bishop? // Задача 1398. Слон и пешка 9 июл 2026 23:39 Just according to problem statement it's white wins :), so looks weird coder ADMIN! // Задача 2137. Динамическая сложность строки 9 июл 2026 22:45 Please, check 142 test, C++ fread failed for this test case. scanf accepted. After fread I can try trim space symbols (ASCII code <= 32) from start and end, any more WA142. Alexandru Farcasanu Any hint? [5] // Задача 1915. Руины титанов: воссоздание былого 20 окт 2012 23:26 Any hint for solving this problem? green_smile Re: Any hint? // Задача 1915. Руины титанов: воссоздание былого 21 окт 2012 00:17 may be stack? Ilya Shakirov [Perm SU] Re: Any hint? [2] // Задача 1915. Руины титанов: воссоздание былого 21 окт 2012 13:05 number of possible operations is only 1m Bogatyr Re: Any hint? // Задача 1915. Руины титанов: воссоздание былого 21 окт 2012 16:50 > number of possible operations is only 1m Hah! Somehow reading this here (even though it's clear in the problem statement) made me see the way...thanks. Dmi3Molodov best Hint!!! // Задача 1915. Руины титанов: воссоздание былого 9 июл 2026 22:39 std::copy_backward ONCE! Didi (OSU11) Re: Any hint? // Задача 1915. Руины титанов: воссоздание былого 4 ноя 2012 19:05 memcpy (for c++) and million.., and not any more ;p coder How solve it O(N) ? // Задача 2137. Динамическая сложность строки 9 июл 2026 22:09 Denis Koshman If you have WA12 [2] // Задача 1269. Антимат 25 авг 2008 19:08 Try this test: 2 abc b 1 abc Correct answer: 1 1 sailingoat Re: If you have WA12 [1] // Задача 1269. Антимат 29 янв 2025 22:34 THANK YOU SO MUCH ! ! !! Solver Re: If you have WA12 // Задача 1269. Антимат 9 июл 2026 21:04 Thanks :) Arthas Please add these tests. [2] // Задача 1466. Магический квадрат 19 май 2009 07:14 3 5 1 4 5 7 3 8 2 4 4 7 5 3 7 7 0 3 5 2 5 1 5 3 4 3 8 8 8 6 0 6 6 1 I got tle on these tests.But I got AC. 👨🏻💻 Spatarel Dan Constantin Re: Please add these tests. [1] // Задача 1466. Магический квадрат 2 авг 2019 18:42 My AC solution outputs "NO" on both of those test cases. Igor Parfenov Re: Please add these tests. // Задача 1466. Магический квадрат 9 июл 2026 19:16 Answer to second test is YES. And, moreover, there are 840 ways to fill the square. Upd. Sorry, forgot about constraint a[0][0]=0. (But, if ignore it, 840 is correct number.) Edited by author 09.07.2026 19:19 Solver Complexity // Задача 2226. Графство белок 9 июл 2026 12:20 O(N) for RAM and CPU, don't know why memory limit is that high. Based on classics for tree diameter. Sq1 Start time is 0 or 1 ? [1] // Задача 2009. Очереди в столовой 7 янв 2017 00:02 Solver Re: Start time is 0 or 1 ? // Задача 2009. Очереди в столовой 9 июл 2026 08:55 Doesn't matter, could be -1000 Lomir What is the maximum number of divisions needed? [3] // Задача 1468. Дробь 3 июл 2007 18:02 What is the maximum number of divisions needed to get the full period? I got TLE this O(n^2) algo there n is the number of divisions. Lomir Re: What is the maximum number of divisions needed? [2] // Задача 1468. Дробь 3 июл 2007 18:15 O(n*lg n) from number of divisions also TLE. But why...? Lomir Re: What is the maximum number of divisions needed? [1] // Задача 1468. Дробь 3 июл 2007 18:26 O(n) AC in 0.234 O(n^2) memorization of prev remainders in vector with linear search O(n*lg n) memorization of prev remainders in set O(n) just used bitset<10000> cause all remainders is less then 10000 But why O(n*lg n) TLE!?!?!? Solver Re: What is the maximum number of divisions needed? // Задача 1468. Дробь 9 июл 2026 07:22 just remember position for each remainder, once stepped over again - period detected. O(b) memory, O(b) runtime linjek AC [1] // Задача 1016. Кубик на прогулке 9 авг 2014 16:51 You can solve that with algo Djikstra. We have 6!*8*8 vertex (hash of cube and point) . And all vertexs have <=4 edges. P.s. sry for English ) Edited by author 09.08.2014 16:51 Solver Re: AC // Задача 1016. Кубик на прогулке 9 июл 2026 02:00 there are only 24 orientations
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